3x^2-16x-12=3x^2+4x-20x-12

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Solution for 3x^2-16x-12=3x^2+4x-20x-12 equation: 



3x^2-16x-12=3x^2+4x-20x-12

We move all terms to the left:

3x^2-16x-12-(3x^2+4x-20x-12)=0

We get rid of parentheses

3x^2-3x^2-16x-4x+20x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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